LESSON 3 Factorial of a number using recursion C Programming

Factorial of a number using recursion

#include<stdio.h>

#include<conio.h>

int fact(int);

void main()

{

int n,f;

clrscr();

printf("Enter the limit");

scanf("%d",&n);

f=fact(n);

printf("factorial is %d",f);

getch();

}

int fact(int x)

{

int p;

if(x==0)

return(1);

else

{

p=x*fact(x-1);

}

return(p);

}

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LESSON 4 Checking whether a string palindrome C Programming

Cheking whether a string palindrome

#include<stdio.h>

#include<conio.h>

#include<string.h>

void main()

{

 int n,i,flag=0,j;

 char a[32];

 clrscr();

 printf("enter the string");

 scanf("%s",a);

 n=strlen(a);

 for(i=0,j=n-1;(i<n)&&(j>0);j--,i++)

  {

     if(a[i]!=a[j])

       flag=1;

  }

     if(flag==1)

     printf("the string is not palindrom");

     else

     printf("the string is palindrome");

     getch();

}

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LESSON 5 Product of two matrix C Programming

Product of two matrix

#include<stdio.h>

#include<conio.h>

void main()

{

int m,n,p,q,i,j,k,a[20][20],b[20][20],c[20][20];

clrscr();

printf("enter the no of rows & columnsof matrix 1\n");

scanf("%d%d",&m,&n);

if(m==0||n==0)

{

printf("matrix is not possible");



}

printf("enter the array elements\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

{

scanf("%d",&a[i][j]);

}

}

printf("enter the no of rows & columnsof matrix 2\n");

scanf("%d%d",&p,&q);



if(p==0||q==0)

{

printf("matrix is not possible");

}

printf("enter the array elements\n");

for(i=0;i<p;i++)

{

for(j=0;j<q;j++)

{

scanf("%d",&b[i][j]);

}

}

printf("the  matrix 1 is \n\n");

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

{

printf("%d\t",a[i][j]);

}

printf("\n\n\n");

}



printf("the  matrix 2 is \n\n");

for(i=0;i<p;i++)

{

for(j=0;j<q;j++)

{

printf("%d\t",b[i][j]);

}

printf("\n\n\n");

}

printf("\n");

if(n==p)

printf("multiplication is possible\n");

else

{

printf("multiplication is not possible");

exit(0);

}

for(i=0;i<m;i++)

{

for(j=0;j<q;j++)

{

c[i][j]=0;

for(k=0;k<n;k++)

{

c[i][j]=c[i][j]+(a[i][k]*b[k][j]);

}

}

}

printf("product is\n\n");

for(i=0;i<m;i++)

{

for(j=0;j<q;j++)

{

printf("%d\t",c[i][j]);

}

printf("\n\n\n");

}

getch();

}

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LESSON 6 Details of two students and their three marks m1,m2,m3 C Programming

Details of two students and their three marks m1,m2,m3

#include<stdio.h>

#include<conio.h>

void main()

{

struct stud{

    char name[20];

    int m1;

    int m2;

    int m3;

    int m4;

    int total;

    char grade[20];

    }a[100],temp;



 int n,i,j ;

 clrscr();

 printf("enter no. of students");

 scanf("%d",&n);

 for(i=0;i<n;i++)

 {

printf("enter details \nname,m1,m2,m3,m4");

    scanf("%s",a[i].name);

    scanf("%d%d%d%d",&a[i].m1,&a[i].m2,&a[i].m3,&a[i].m4);

    a[i].total=a[i].m1+a[i].m2+a[i].m3+a[i].m4;

    }

 for(i=0;i<n;i++)

 {

 for(j=0;j<n-i;j++)

 {

 if(a[j].total<a[j+1].total)

  {

  temp=a[j];

  a[j]=a[j+1];

  a[j+1]=temp;

  }

  }

  }printf("\nname\tm1\tm2\tm3\tm4\ttotal");

 for(i=0;i<n;i++)

 printf(" \n%s\t%d\t%d\t%d\t%d\t%d",a[i].name,a[i].m1,a[i].m2,a[i].m3,a[i].m4,a[i].total);

 getch();

 }

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LESSON 2 Expansion of sin(x) with a limit(n) C Programming

Expansion of sin(x)  with a limit(n)

#include<stdio.h>

#include<conio.h>

#include<math.h>

int fact(int);

void main()

{

int x,n,k,i;

float s=0;

printf("Enter x and n");

scanf("%d%d",&x,&n);

for(i=0;i<n;i++)

{

k=fact(i*2);

if(i%2==0)

s=s+(float)(pow(x,i*2)/k);

else

s=s-(float)(pow(x,i*2)/k);

}

printf("sum is %f",s);

getch();

}

int fact(int a)

{

int f=1,j;

for(j=1;j<=a;j++)

f=f*j;

return(f);

}

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LESSON 1 Prime number up to a limit C Programming

Prime number upto a limit

Here we importing to library (stdio.h)C Standard Input and Output Library for Input and Output operations. and conio is a c header file and not part of c standard library ,it is used MSDOS compilers to console Input/Output

here we have main function and declared n,i,j,k variables with integer properties
for storing the values to n we use %d followed by &n

Next is for loop section
for(i=2;i<n;i++) →means that i=2  to n , we have n value stored in int n variable , so if n is 10 then first it start from i=2 then check 2<10 ie is true so it add 1 to i  so i→3 then goto next for loop

and so on. for printing a variable i we use &d, then followed by i
At last we use getch() function to get a still screen 

#include<stdio.h>

#include<conio.h>

void main()

{

int n,i,j,k=0;

clrscr();

printf("Enter the limit");

scanf("%d",&n);

for(i=2;i<n;i++)

 {

  for(j=2;j<i;j++)

  {

  if(i%j==0)

  k++;

  }

  if(k>2)

  printf(" %d",i);

 }

 getch();

}

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